I'm trying to run the code in Python below and keep getting invalid syntax. What's wrong? Thanks for any help!
def even(n):
if n%2==0
#Enter a Number
def main():
n=int(input("Enter a number: "))
#If even print "Number is even"
if(even(n)):
print("The number is even")
#If odd print "Number is odd"
else:
print("The number is odd")
main() #Call the main function
def even(n):
if n%2==0:
return True
else:
return False
#Enter a Number
def main():
n=int(input("Enter a number: "))
#If even print "Number is even"
if(even(n)):
print("The number is even")
#If odd print "Number is odd"
else:
print("The number is odd")
main() #Call the main function

I'm trying to run the code in Python below and keep getting invalid syntax. What's wrong?...
THIS IS THE CODE I AM TRYING TO RUN code # def main(): #Reading a as an integer a = int(input("Enter value for a: ")) #reading b as an interger b = int(input("Enter value for b: ")) #reading n as an integer n = int(input("Enter value for n: ")) # displaying if a and b are congruent modulo n, this is True if a and b #both returns same remainder when divided by n if a % n == b...
while trying to run this in python, i keep getting the error TypeError: int() can't convert non-string with explicit base. any way to fix this? def binaryToDecimal(n): return int(n,2) if __name__ == '__main__': num3 = int(input("Enter value to be converted: ")) print(binaryToDecimal(num3))
In Python, please change this function so if someone inputs an invalid age (string, float, number below 0), print "wrong". Use the "isdigit()" function -------------------------- def age_name(): name = input("Enter name:") age = int(input("Enter age:")) print("Hello", name) if(age <= 18): print("Child") elif(age <= 64): print("Adult") else: print("Senior")
I'm trying to simply print hello world but it's giving me
invalid syntax when I try to run it from the terminal and I dont
understand why.
python ./age.py Desktop File "./age.py", line 1 >>> print('Hello World') SyntaxError: invalid syntax
(python)
[30] Implement exception handling with ValueError here in the following code: There are three blanks you need to fill in. Write the answers in the space given for you. class Area: def __init__(self): self.x = 0 def setX(self n): if n<=0: else: self.x = n #main code a = Areal) inputValue = int(input("Enter a Value that is greater than 0")) a.setX(inputValue) print("Invalid Input Value Entered")
What's wrong with my code? : I'm trying to use recursive functions to display and count all the even numbers of an array. However, I can't seem get the program output the number of even integers . Here's the output I want: Here are the 5 even numbers: // Luckily, however, my code does output all the even numbers. But, I also want the program to tell me how may even integers there are. 2 8 14 18 22 MY...
IN PYTHON: The following code contains syntax errors. Assuming the code should read in a name, and output a message indicating if the last name is "Smith". REWRITE THIS STATEMENT CORRECTLY. value = input(" enter your name using LAST, FIRST format") val= value.split(",") if value[0] ="Smith": print("your last name is common") else val[0] != "Smith": print("not so common") print(]"ODD")
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: back to classroom run Instructions from your teacher: import random def get_message(user_num, rand_num): Eo von AwNP Complete the get_message function so if user_num is equal to rand_num, return "You picked the same number as the computer!" if user_num is less than rand_num, return "Your number is smaller than the computer's number." if user_num is greater than rand_num, return "Your number is higher than the computer's number." Comment out the call to main when trying to pass the tests. 11...
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