The human eye disease retinitis pigmentosa is caused by a loss of function mutation (rp) in the gene PRPF31. The disease is expressed when combined with wildtype allele 1 (rp+1) in a heterozygote, but not expressed when combined with wildtype allele 2 (rp+2) in a heterozygote. When comparing the number PRPF31 mRNA transcripts in the eyes of rp/rp+1 and rp/rp+2 individuals, researchers have found higher number of functional PRPF31 mRNAs in the eyes of rp/rp+2 individuals.
This is an example of [ Select ] ["incomplete penetrance", "incomplete dominance", "pleiotropy", "variable expressivity"] caused by [ Select ] ["haplosufficiency", "haploinsufficiency"] when is rp occurs in the same genotype as rp+2
Retinitis pigmentosa (RP) is a set of hereditary retinal disorder caused by a loss of function mutation (rp) in the gene PRPF31 (Human pre-mRNA splicing factor 31 (PRPF31). The disease is expressed when combined with wildtype allele 1 (rp+1) in a heterozygote, but not expressed when combined with wildtype allele 2 (rp+2) in a heterozygote. Among inherited retinal dystrophies (IRDs) RP is in itself a large and genetically heterogeneous group of disorders. RP can be transmitted with an autosomal dominant, recessive or X-linked mode of inheritance. The PRPF31, is a ubiquitously expressed component and they are either large deletions or result in a premature termination codon. The mutant transcript is cleared through nonsense-mediated decay (NMD). The photoreceptors are more sensitive to PRPF31 levels due to their high demand on the spliceosome machinery and follow a special splicing program that produces high levels of alternatively spliced transcripts. This is the only cause retinal disease in the heterozygous state. To correlate with protein levels, the mode of action of PRP31 mutations appears to be haploinsuciency, a situation in which the total level of a particular protein produced by the cell is about half of the normal level and that is not sufficient to permit the cell to function normally.
Hence this is an example of incomplete dominance, caused by haploinsufficiency when is rp occurs in the same genotype as rp+2.
The human eye disease retinitis pigmentosa is caused by a loss of function mutation (rp) in...
The human eye disease retinitis pigmentosa is caused by a loss of function mutation (rp) in the gene PRPF31. The disease is expressed when combined with wildtype allele 1 (rp+1) in a heterozygote, but not expressed when combined with wildtype allele 2 (rp+2) in a heterozygote. When comparing the number PRPF31 mRNA transcripts in the eyes of rp/rp+1 and rp/rp+2 individuals, researchers have found higher number of functional PRPF31 mRNAs in the eyes of rp/rp+2 individuals. This is an example...
Tay-Sachs disease is an autosomal recessive disorder caused by a mutation in the HEXA gene that results in progressive deterioration of the nervous system. Affected indivisuals usually die by age 4. Let D represent the wildtype allele and d the disease-causing allele. Because the Tay-Sachs disease allele has been observed at relatively high frequencies in several human populations, it has ocassionally been suggested that this locus may be subject to balancing selection due to heterozygote advantage. Here we will explore...
multiple choice questions: 1- What fraction of the progeny will show a recessive phenotype for just one gene in a cross between AaBbCc x AaBbCc? A. 7/16 B. 9/64 C. ¼ D. 27/64 E. 26/64 2- Siblings share what percentage of their alleles? A. ½ B. ¼ C. 1/8 D. 1/10 E. 1/16 3- In a heterozygote, one allele conceals the presence of another. This is Mendel's: A. principle of segregation. B. principle of independent assortment. C. principle of dominance....
Question 9 (1 point) Achrondroplasia is a form of dwarfism caused by a dominant allele. The homozygous dominant genotype causes death, so individuals who have the condition are all heterozygous. If a person with achondroplasia mates with a person who does not have achondroplasia, what percentage of their children would be expected to have achondroplasia Question 9 options: A) 0% B) 50% C) 75% D) 100% Question 10 (2 points) This is an example of incomplete dominance. Let H-curly hair and...
Multiple Choice
1. You count 1000 seeds from a monohybrid cross (i.e., single-locus heterozygote crossed with single-locus heterozygote). How many seeds do you expect to display the dominant phenotype? a. 1000 b. 750 c. 500 d. 250 2. Which of the following is among the purposes of a genetic dissection analysis? a. To determine how two alleles at a locus interact with one another. b. To determine the order of intermediaries in a genetic pathway. c. To determine whether a...
1. Animals can teach us genetics. Match Codominance Show a dominant and recessive relationship _An allelic series A dominant homozygote is lethal Coat coloration is determined by 2 genes Shows variable expressivity A qualitative, or continuous, trait involving polygenes Females mosaics for X-linked heterozygous color genes A. Manx cat B. Coat coloration rabbits C. Labrador retriever dogs D. Piebald spotting in beagles E. A and B blood alleles F. A and O blood alleles G. Calico cat H. Height of...
Osteogenesis imperfecta is a disease caused by non-functional A. Dominant; chloride ion channel B. Dominant; collagen C. Dominant; hemoglobin D. Recessive; chloride ion channel E. Recessive; collagen AB. Recessive; hemoglobin 14. Sickle cell disease is an example of many distinct traits (and therefore causes many symptoms). A. codominance B. pleiotropy C. incomplete dominance D. multiple allelic trait E. x-linked inheritance because it is caused by one abnormal gene that affects 15. In a Punnett square: A. the results show the...
Which of the following is TRUE of incomplete penetrance? Select one: a. Epistatic interactions can result in incomplete penetrance in some cases. b. Environmental factors do not influence penetrance. c. Incomplete penetrance implies that some individuals will experience less severe forms of disease, such as cancer or Alzheimer's. d. Incomplete penetrance is never observed with Huntington's disease e. Incomplete penetrance refers to cases in which individuals developing a particular disease (e.g., cancer or Alzheimer's) lack the typical genotype for this...
2. A dominant allele H reduces the number of body bristles that Drosophila flies have, giving rise to a “hairless” phenotype. In the homozygous condition, H is lethal. An independently assorting dominant allele S has no effect on bristle number except in the presence of H, in which case a single dose of S suppresses the hairless phenotype, thus restoring the "hairy" phenotype. However, S also is lethal in the homozygous (S/S) condition. What ratio of hairy to hairless flies...