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11. Simplify the following function to SOP: F (HOPE) = m(0,2,6,7,8,10)
Given the following SOP equation.
F = Σ (2,4,5,6,10,12,13,14)
FEQ=
2- Draw the logic circuit for the unsimplified SOP equation.
3-
Using Boolean algebra, simplify the SOP equation
(FEQ) and draw the logic circuit for the simplified SOP
equation.
F =
Fill-out the Truth Table and write the unsimplified SOP equation. FEQ FCircuit 11 11
Simplify the expression to get a (SOP) sum of product result with 3 terms. F = (A + C)(B’ + D)(A + C’ + D’)(B’ + C’ + D’)
13. Find the simplified SOP for the given function. F(BEST) = m(1,3,5,7,10) + d(2,11,12,13,14,15)
Simplify the following functions using a K-map and obtain the minimal SOP and minimal POS equations for each function. a) ?(?, ?, ?, d) = ∑ ?(0,2,4,11,13,15) b) ?(?, ?, ?, ?) = ∑ ?(1,3,5,7,8,9,11,12,14) + ??(0,2,6,10)
For the function, F = Σ m (0,4,5,7,8,11,12) Use Quine McClusky’s method to simplify function F and implement the function using basic building blocks
Problem 1 Simplify the following expression in SOP form and implement it with only Equivalents: AND
4. Simplify the following Boolean function F, together with the don't care conditions d, and then express the simplified function in a. Simplified sum-of-products expression (10 points) b. Simplified Product-of-Sums expression (10 points) F (A,B,C,D)-?m(5,6,7, 12, 14, 15) +zd (39, 11, 15) (Use K-maps for the simplification)
Simplify the following function and then write VHDL program: F(x1, x2, x3) 2 m (0, 1, 3, 4, 5,6)
6. Find the minimum-cost SOP and POS forms for the function: f(x1, X2, X3, X4, X5) = > m (1,3,4,7,9,10,12,17,19,20,23,25,26,28,30) + D(14,21,24,29) 7. Problem 2.45 A four-variable logic function that is equal to 1 if any three or all four of its variables are equal to 1 is called a majority function. Design a minimum-cost SOP circuit that implements this majority function.
Using Boolean algebra, simplify the following into the simplest SOP expressions you can. SHOW ALL STEPS. (A+B)(A'+B)= A'(A+B)= (A XOR B)'= A' + AC=