Question

PR3 v 280.17mV R1 PR2 PR1 11,266.82htv v-273.71mV 1002 100m 3 V1 C1 1V 10kHz 0° 4 10uF

Q: Calculate the amount of phase difference between the source voltage and the current in the circuit.

Answer 1

Total impedance of the circuit

$Z=R+j( \omega L-\frac{1}{\omega C})$

And the phase difference

$\theta = tan^{-1} \frac{( \omega L-\frac{1}{\omega C})}{100}$

$\omega=2\pi f,\ f=10^4 Hz$

After putting the value

$\theta= 89.0879\degree$