Question

8 A case of disputed paternity involves a woman, her children (1, 2 and 3), and two men Y and Z). The analysis is limited to the ABO and Rh blood group systems. Using the space below, and assuming that only YorZ could be the biological father, assign each child to his/her possible father. You can use either Punnett squares for each trait, or the process of Mother Possible Fathers Children Possible father for each child elimination. There may be more than one possible A, Rh Y B, Rh+ 1 A, Rh+ father for a particular child. The phenotypes are shown Z AB, Rh- 2 AB, Rh+ in the table 3 O, Rh- Remember that in the ABO blood group system, A and B are codominant, and both are dominant over the recessive O allele, Rh has two alleles, Dand d. Rh- is the recessive form, associated with the genotype dd.

Answer 1

Mother father AY A, Rh- B, Rht IBIB 50% B Possible genotypes of blood groups Mother IA IO IAIA father - IB IB IBI" Case I Mother IAIO father offsprings I AIB IA IB IB I' IBI" 50% AB Case I Mother IA I father IBIO offsprings IA IB IAIO IBIO Iº I 257 B 25% 0 Case II Mother IAIA Father IBIB offspsings 100% AB I AIB father IBIO 25% AB 25% A Case N Mother IAIA offsprings IA IB IAIO IA IB IAIO 50% AB 50%. A

Father Mother RW- Rht Genotype ++ OR t- Case I Mother father ++ + + +- +- t- + - 100% offsprings Rht Case I Mother father t- ot + +- +- 50% Rht 50% Rh- # Mother Father z A, Rh- AB Rh Possible IA IA / IAI X genotypes of blood groups I AIB Father Mother Case I. Mother IA IA father I4 IB Offsprings IATA IAIS TATA TAIB 50% A 50% AB Case I. Mother It To father IA IB offsprings IAIA IIb II° II° 50% A 25% AB 25% B

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