Question

Problem (5): Design the power and relay control circuit to start DC motor as following: 1) Start by pressing start pushbutton and stop by pressing stop pushbutton. Start work with inserting resistance Rland (2 R2. After five seconds from starting we put Ri out of function and after 10 seconds from .starting we put R2 out of function

Answer 1

Problem (5): Design the power and relay control circuit to start DC motor as following: 1) Start by pressing start pushbutton and stop by pressing stop pushbutton. Start work with inserting resistance Rland (2 R2. After five seconds from starting we put Ri out of function and after 10 seconds from .starting we put R2 out of function

Solution:

There are 3 contactors Q1, Q2, Q3 When Start button is pressed, Q1 coil gets energised, and remains energised through the holding contact of Q1 and DC motor gets connected to DC supply through Q1 contactor and resistances R1 and R2. So, the motor starts Now, there are two ON delay timers T1 and T2. T1 and T2 has delay on pick up (DOP) of 5 secs and 10 secs respectively. So after 5 secs from starting, Q2 energises and R1 resistance is bypassed. And after 10 secs from starting, Q3 energises and R2 is bypassed. When Stop button is pressed Q2 deenergises and Motor gets disconnected from the supply system and motor stops.

32 FIELD 33 mm R2 mm 21 Ri Fuse De Supply DC MOTOR I di contactor F2 F4D 03 73 Start To T2 Stop 8, 182 183 - Timer T1 DOP:5 See Timer T2 DOP:10 SIC
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