Question

Using Nodal analysis, for values provided, solve for vį, in V. 11=5.0A 1₂=5.5A R1 = 0.9 ohms R3 = 1.5 ohms 1 592 Rz 3 R 12 0

Answer 1

V₂. 52 JIR3 d. IRI IR 11.52 Iz 5.5A R3 Ri 30.12 I=5A KCL at Node 0 :- I = IRITIR Y IRI= 그이드 Vi 09 IR = VI-V2 but the value in equin + V, -12 5 09 5 5 = 10 % 10 vi 9 + V-V2 5 504&gvi-gu 45 5 - 225=59v.-912 5901 - 9 V2 =225 KCL at Node ② IR = I R3 + Iz V2 IRSE V 2 L VI-V2 1 IR = R3 1.5

V, V2 = V₂ 1.5 + 5.5 in V-V₂ Vive V₂ + 8.25 1.5 15 V, -1.5V2 = 5V2+ 4-1:25 ov 1.5V, -6'512 = 41:25 Sloving the equin & ♡ V2 = -5.66 v V=2.95 V And