Question

A recent survey of 1044 employees found that 34​% of them would lay off their bosses if they could. Complete parts a through d below based on a random sample of 10 employees.

a. What is the probability that exactly three employees would lay off their​ boss?

The probability is ____

​(Round to four decimal places as​ needed.)

b. What is the probability that three or fewer employees would lay off their​ bosses?

The probability is ____

​(Round to four decimal places as​ needed.)

C). What is the probability that five or more employees would lay off their​ bosses?

D) What are the mean and standard deviation for this​ distribution?

Answer 1

Solutions Given question is an example of binomial distribution, where sample size, na lo. that employees would lay off their bosses ,p=34% = 0.34 probability of not buying off their bosses nel 1-2- probability = 0.66

Lor, reandom Variable XE noo of employees that would their hya oft bosses. Then. p(x=0) = 'com pe 2012 P(x=3) lo C, (0.3439.60.66)? 0.25729 10.2573 (any (b) P(x=3) Å locx p* 10X X =D È Peru (0.35" (o.seyond] 0.54LOG : 0.5411 TP(X3) =) (Any) le) PCX25) = 1- P(x < 5) L- Ĉ (10cm (0.343(o.coples -D 1 -0.77301 - ०.२२७११ ~0.2270 IP (x + 5): 0.2210 (Any) (d) for Binomial distribution EX. = 10x 0.34 = 34. ..panpa Mean, an, M: 3.4 (Ang) 7 And standard deviction, 8= Jupq 3.440.66 - 1.44799 1-50 => 1.50 (Any) Thanks you :) -X