Question

In a recent​ study, it was found that 59​% of college students have pulled an all...

In a recent​ study, it was found that 59​% of college students have pulled an all nighter at least once in the past year to complete work for their courses. We believe that this follows a binomial distribution. Complete parts ​(a) through ​(e) below based on a random sample of 12 college students

​a) What is the probability that exactly 6 of the college students pulled an all​ nighter?

The probability is

​(Round to four decimal​ places.)

​b) What is the probability that 44 of the college students did not pull an all​ nighter?

The probability is.

​(Round to four decimal​ places.)

​c) What is the probability that less than 6 college students pulled an all nighter​?

The probability is.

​(Round to four decimal​ places.)

​d) What is the probability that 3 or more college students pulled an all nighter​?

The probability is

​(Round to four decimal​ places.)

​e) What is the expected number and standard deviation of the number of college students that pulled an all nighter if the number of college students surveyed is

178?

The expected number of college students that pulled an all nighter in this binomial sample is

The standard deviation of this binomial distribution is

​(Round to two decimal ​places.)

0 0
Add a comment Improve this question Transcribed image text
Answer #1

This is a binomial distribution question with

n = 12

p = 0.59

q = 1 - p = 0.41

where

a) x = 6

c)

d)

e) Since we know that

Please hit thumps up if the answer helped you

Add a comment
Know the answer?
Add Answer to:
In a recent​ study, it was found that 59​% of college students have pulled an all...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A selective college would like to have an entering class of 1000 students. Because not all...

    A selective college would like to have an entering class of 1000 students. Because not all students who are offered admission accept, the college admits more than 1000 students. Past experience shows that about 83% of the students admitted will accept. The college decides to admit 1200 students. Assuming that students make their decisions independently, the number who accept has the B(1200, 0.83) distribution. If this number is less than 1000, the college will admit students from its waiting list....

  • A recent study found that 41% of college students engage in binge drinking (5 drinks at...

    A recent study found that 41% of college students engage in binge drinking (5 drinks at a sitting for men, 4 for women). After hearing of the result, a professor surveyed a random sample of 244 students at his college and found that 92 admitted to binge drinking in the last week. Should he be surprised at this result? Explain. Select the correct choice below and fill in the answer box to complete your choice. (Round to three decimal places...

  • The times that college students spend studying per week have a distribution skewed to the right...

    The times that college students spend studying per week have a distribution skewed to the right with a mean of 8.6 hours and a standard deviation of 2.8 hours. Find the probability that the mean time spent studying per week for a random sample of 16 college students would be more than 9.1 hours. Round your answer to two decimal places. Attach File Browse My Computer Browse Content Collection Browse Dropbox QUESTION 7 The GPAs of all students enrolled at...

  • Almost all medical schools in the United States require students to take the Medical College Admission...

    Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate the mean score μ of those who took the MCAT on your campus, you will obtain the scores of an SRS of students. The scores follow a Normal distribution, and from published information you know that the standard deviation is 10.8. Suppose that, unknown to you, the mean score of those taking the MCAT on your campus is 500. In...

  • Almost all medical schools in the United States require students to take the Medical College Admission...

    Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate the mean score u of those who took the MCAT on your campus, you will obtain the scores of an SRS of students. The scores follow a Normal distribution, and from published information you know that the standard deviation is 10.8. Suppose that, unknown to you, the mean score of those taking the MCAT on your campus is 495. In...

  • Almost all medical schools in the United States require students to take the Medical College Admission...

    Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate the mean score y of those who took the MCAT on your campus, you will obtain the scores of an SRS of students. The scores follow a Normal distribution, and from published information you know that the standard deviation is 10.8. Suppose that, unknown to you, the mean score of those taking the MCAT on your campus is 500. In...

  • Almost all medical schools in the United States require students to take the Medical College Admission...

    Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate the mean score μμ of those who took the MCAT on your campus, you will obtain the scores of an SRS of students. The scores follow a Normal distribution, and from published information you know that the standard deviation is 10.810.8 . Suppose that, unknown to you, the mean score of those taking the MCAT on your campus is 495495...

  • A college research group reported that 46% of college students aged 18-24 would spend their spring breaks relaxing at h...

    A college research group reported that 46% of college students aged 18-24 would spend their spring breaks relaxing at home Complete parts a through d below 2009. A sample of 150 college students was selected. a. Calculate the standard error of the proportion. (Round to four decimal places as needed.) b. What is the probability that less than 40% of the college students from the sample spent their spring breaks relaxing at home? P(Less than 40% of the college students...

  • A recent study found that 43% of college students engage in binge drinking (5 drinks at...

    A recent study found that 43% of college students engage in binge drinking (5 drinks at a sitting for men, 4 for women). After hearing of the result, a professor surveyed a random sample of 295 students at his college and found that 115 admitted to binge drinking in the last week. Should he be surprised at this result? Explain Select the correct choice below and fill in the answer box to complete your choice (Round to three decimal places...

  • The scores of students on the SAT college entrance examinations at a certain high school had...

    The scores of students on the SAT college entrance examinations at a certain high school had a normal distribution with mean μ = 547.9 and standard deviation σ = 25.5 . (If necessary, round answers below to at least four decimal places.) (a) What is the probability that a single student randomly chosen from all those taking the test scores 551 or higher? ANSWER:____ For parts (b) through (d), consider a simple random sample (SRS) of 25 students who took...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT