Question

A college research group reported that 46% of college students aged 18-24 would spend their spring breaks relaxing at home Complete parts a through d below 2009. A sample of 150 college students was selected. a. Calculate the standard error of the proportion. (Round to four decimal places as needed.) b. What is the probability that less than 40% of the college students from the sample spent their spring breaks relaxing at home? P(Less than 40% of the college students from the sample spent their spring breaks relaxing at home) (Round to four decimal places as needed.) c. What is the probability that more than 50% of the college students from the sample spent their spring breaks relaxing at home? P(More than 50% of the college students from the sample spent their spring breaks relaxing at home) (Round to four decimal places as needed.) d. What is the probability that between 48% and 58% of the college students from the sample spent their spring breaks relaxing at home? | P(Between 48% and 58% of the college students from the sample spent their spring breaks relaxing at home) (Round to four decimal places as needed.)

Answer 1

P -46. -0.4G a-I-O-96 0.64 150 pa O.46x0.59 0.040t PCPL 40da) b =PCP< 0.4) =P(そく0-4-0-46 O-040t -PC 4t) D 0t08 -1Cpo.5)ニPC z> 0.5-0-46 0-040子 9 PCPYS04) 0.1635 PCE0.98) d PC48t6 Pe 581) - PC0-48 pe o.58) PC O-48 -0.4-6 L7L0058-0.46 O.992 t62195) 0-040千 0.0404 0.3105