Question

1a The figure below shows two perpendicular front-reflecting mirrors. A ray of light is incident on the vertical mirror at o; = 15.8°. e Calculate the angle of reflection or off of the horizontal mirror. er = B Optically active molecules have the property of rotating the direction of polarization of linearly polarized light. Many biologically important molecules have this property, some causing a counterclockwise rotation (negative rotation angle), others causing a clockwise rotation (positive rotation angle). For example, a 1.0 & solution of cholesterol causes a rotation of –31.5°. Calculate the transmitted intensity for this solution when placed between 90° crossed polarizers. The incident beam is unpolarized and has an intensity of 23.8 W m4 W Itrans ma

Answer 1

The light ray ineidents at an angle oi = Isigo The the incidents in roy angle at which horizontal mirror ig go - Riz 80- 15.8° 74.2 angle of reflection 74.29 After ISH polariser, intensity I = 2.3.8 11-9 watt/m2 2 The and polarisere makes angle with 1st is Aa 90 - 31.5 58.50 According to Malus law, F, Cso: 11.9 285 58.5" 3,248 wlme