Question

Would like help& explanation of how the genetic distances factor in. thanks!

Three plant genes, A, B, and C, are linked and occur in the following order. Genetic distances are given as map units (m.u.): А. 10 m.u. В. Om.u._C The genes underlie the following phenotypes: A/=blue flowers, a/a = white flowers B/_=tall stems, b/b = short stems CI_ = green leaves, c/c = red leaves You cross two individuals with the following genotypes: AbC/ AC x aBc/aBc you self the resulting F1 the proportion of the offspring that will have white flowers, short stems, and green leaves is (Provide the answer as a decimal number with 4 decimal places):

Answer 1

Answer-

Proportion of having offspring with white flowers (aa), short stems (bb) and green leaves (C_) is 0.0025

The explanation is given below:

10 mu т о с А map distance between A and B gene B and C gene -10 mu .. Crossover frequency between A-B = 10%. 1 O'7. В- с - авс A b c Aьс а во F Н (Abc авс gametes Abc - Fi а во A b c A b c авс (Fixfi) Х авс Aьс A b c авс а во (Abc авс А во abc - 45/. 45. — Б/. - 57. Parental gamete types - 4 90/. cross over types between A and B - 107.

Punnet square Ab C =45% a BC -45% ABC - 5% abc=57. Abc Abo Abc Abo a Bc Abc ABC Abc abc = 45%. abc Abc a b c abc a b c ABC a Bc abc abc - 45%. abc Abc ABC ABC ABC a Bc ABC ABC ABC -57 Abc a b c abc abc abc ABC a b c abc abc 57. 5% X 5% from the selfing between f, we have to find the proportion of offspring having white flowers, short green ( aabbc-) stems and leaves abc From the Punnet square it is clearly obserleed that gametes together can only form om this genotype . SO the proportion of having abc - 57. X 5% abc = 0.05X0.05 -0.0025