Z = (X - Mean) / standard deviation
= ($11,000 - $16,000) / $4000
= -$5000 / $4000
= -1.25
Z value lower than -1.25 is 0.1056
Probability of a cash flow being greater than $11,000 = 1 -
0.1056
= 0.8944 or 89.44%
Probability of a cash flow being greater than $11,000 = 89.44%
Question 3 2 pts Builtrite has calculated the average cash flow to be $16,000 with a...
Builtrite has calculated the average cash flow to be $16,000 with a standard deviation of $4000. What is the probability of a cash flow being greater than $11,000? (Assume a normal distribution.) Group of answer choices A.10.56% B.39.44% C.60.56% D.89.44%
Builtrite has calculated the average cash flow to be $16,000 with a standard deviation of $4000. What is the probability of a cash flow being less than $9000? (Assume a normal distribution.) 4% 09% 41% 46%
Builtrite has calculated the average cash flow to be $16,000 with a standard deviation of $4000. What cash flow would represent the top 3%? (Assume a normal distribution.) 10 $8,480 O $14,850 O $23,520 O $27,450
Builtrite has calculated the average cash flow to be $16,000 with a standard deviation of $4000. What cash flow would represent the bottom 3%? (Assume a normal distribution.) $8,480 $14,850 $23,520 $27,450
Builtrite has calculated the average cash flow to be $16,000 with a standard deviation of $4000. What cash flow would represent the top 3%? (Assume a normal distribution.) $8,480 $14,850 $23,520 $27,450
Builtrite has calculated the average cash flow to be $16,000 with a standard deviation of $4000. What cash flow would represent the top 3%? (Assume a normal distribution.) Group of answer choices A.$8,480 B.$14,850 C.$23,520 D.$27,450
Jerry has calculated the average cash flow to be $16,000 with a standard deviation of $4,000. What is the probability of a cash flow being less than $9,000?
Tim has calculated the average cash flow to be $16,000 with a standard deviation of $4,000. What cash flow would represent the bottom 3%?
This Question: 3 pts 7 of 11 (0 complete) This Quiz: 17 pts possible Question Help The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8.9 cm. a. Find the probability that an individual distance is greater than 209.30 cm. b. Find the probability that the mean for 15 randomly selected distances is greater than 198.50 cm. c. Why can the normal distribution be used in part (b),...
Help please answer all parts
his Question: 3 pts 29 of 34 (13 complete) with a mean of 200 cm and a standard deviation of 8 cm. a. Find the probability that an individual distance is greater than 210.00 cm. b. Find the probability that the mean for 15 randomly selected distances is greater than 198.20 cm c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 307 a. The probability...