Question

The material for the tension specimen has the stress-strain diagram shown. Determine approximately the modulus of elasticity E2. 20 mm (MPa) 550 Ea 400 Ει -€ (mm/mm) 0.002 0.03 4750 MPa 5350 MPa 5850 MPa 6250 MPa MacBook Air 20 DOO 74 # 1 * - 3 $ 4 % 5 & 7 6 I 0 8 9 ER T Y U i

Answer 1

Solution:

(MPa) 550 E2 0.= Young's Modulus , E. 400 Can > & (mm/mm) 0.002 0.08

Modulus of Elasticity, E is nothing but the slope of linear curve of stress-strain.  

Hooke's law stated that, modulus of elasticity is equal to the ration of stress to strain.

Modulus of Elasticity, $E2 =\frac{stress}{Strain}$

$E2 =\frac{(550 - 400)mpa}{(0.03 - 0.002)}$

$E2 =\frac{150}{0.028}$

So, option B) 5350 Mpa.