Given that,
population mean(u)=23
sample mean, x =23.6
standard deviation, s =3.4
number (n)=200
null, Ho: μ=23
alternate, H1: μ>23
level of significance, α = 0.05
from standard normal table,right tailed t α/2 =1.653
since our test is right-tailed
reject Ho, if to > 1.653
we use test statistic (t) = x-u/(s.d/sqrt(n))
to =23.6-23/(3.4/sqrt(200))
to =2.496
| to | =2.496
critical value
the value of |t α| with n-1 = 199 d.f is 1.653
we got |to| =2.496 & | t α | =1.653
make decision
hence value of | to | > | t α| and here we reject Ho
p-value :right tail - Ha : ( p > 2.4957 ) = 0.00669
hence value of p0.05 > 0.00669,here we reject Ho
ANSWERS
---------------
a.
null, Ho: μ=23
alternate, H1: μ>23
b.
sample size is large than 30
test statistic: 2.496
c.
critical value: 1.653
decision: reject Ho
p-value: 0.00669
d.
we have enough evidence to support the claim that they scoring
above 23 on the math portion of the exam.
a through d please A college entrance exam company determined that a score of 23 on...
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is ready for college level mathematics. to achieve this goal, the
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