Question

Can you please help me solve this with its part a b c and d?

(0%) Problem 13: A block of mass m = 3.4 kg is on an inclined plane with a coefficient of friction My = 0.31, at an initial height h=0.63 m above the ground. The plane is inclined at an angle 0 = 47°. The block is then compressed against a spring a distance Ax=0.11 m from its equilibrium point (the spring has a spring constant of k, = 28 N/m) and released. At the bottom of the inclined plane is a horizontal plane with a different coefficient of friction, ul2 = 0.14. After a distance d= 0.17 m, there is another spring (spring constant k2= 6.1 N/m) under which the surface is frictionless. Use energy considerations in this problem. h o H2 wwwwww Otheexpertta.com > * 25% Part (a) Assume the block does not make it all the way to the bottom of the ramp before it comes to rest. What is the x-component of the block's position when it stops? Use an x-axis parallel to the incline, with the positive direction pointing down the incline and the origin at the spring's equilibrium position. This should not depend on the initial height of the block, only on the angle. Grade Summary Deductions 0% x} = Ax - ((kı ( Ax))/(2 mg (M COS(O) - sin(O))) Potential 100% 9 HOME cos(a) sin(a) cos(0) sin(0) cos(O) sin(O) ( ) 7 8 14 5 6 Submissions Attempts remaining: 49 (0% per attempt) detailed view 0% a Δx H1 / 1 2 3 0 d END + - 0 Vol BACKSPACE ki m t DEL CLEAR Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 4 Feedback: 0% deduction per feedback. A 25% Part (b) Let us now assume the values are such that the block does reach the bottom of the ramp. Find the speed of the block, in m/s, when it reaches the end of the ramp. Treat the block as a point. A 25% Part (c) Once the block reaches the bottom, it encounters a new coefficient of friction. What distance x, in meters, could the block travel on this surface before stopping if no obstacles were in the way? Assume the size of the block is negligible in transitioning from the ramp to the plane. A 25% Part (d) After a distance d on the surface with coefficient uz, the block encounters a frictionless surface and a spring with constant kz. Calculate how far the spring is compressed As in m when the block comes to rest.

Answer 1

In part A there's is no ∆X-

You should enter only the final answer
N. Los Teul initial energy E = Potential t spring ks į ngrosso mg mgh + 1 ķ(AN² block and Wook done This energy is utilised in moving د را by friction is W = Fqxok h. of = ungeason Mmg tosox y bu = lg hoeaua puj roletos x-426u = E; = Eftw s-you mgxsone a ring x cos ♡ SOOX mght - 2*, (A x ² 2 k, (x² Mg x (M coso sino) K, (AX) 2[rcos@-sino) mg x, 2 X, (axy ? 2 (M. Coso- sino) mg you should enter only 06:40 ") fomg boso sno)) (k,

Now. initial energy E = mght 2 k, lex)? = 3.4x9:8)X 0:63+ Ź(28X60-032 I 21-182 42 J -wook done by friction = wa M mg rosor EM, og roso t hsino) = Mmgh Tano F 6.31% 3. 4x9-81X0.63 tan 47 6.0744, >> energy = £mv² = 2 (3.4) v² 1.72 E = Wt Ef 21:18 = 6:07 +1.772 15.11 Ev² 1.7 V=V8:88823 = 2.98! V=2.98 m/s

으 $ < -> Energy Emra = 1/2 (34) x (2-98)3 z 15.11 ] - twork done by friction W = M₂ mg xd -0-14x34x9.81%d 4669560 WEE 4.669560 = 15:1) di 3.2358 d=3.24 m d but d=817m of Mz surface. Final energy = ½ kg x² į Kgx'= E; -W 2 2 16.152² 3:05 x = 15.11 = 1511 - 4.06596 d 4.66596x017 14.31678 3:05 d=√4.69402 x² 2 = 2.16657 a= 8.1666 m