Question

Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 K2, R2=8 K2, R3=5.1 K2, R4=6 KN, R5=14 KN, R6=4.2 KS, RL=10.3 KS, V1=1V, 12=0.5 mA and V3=3.2 V. R6 R1 R5 Vo w + * RL + 12 R2 V1 R3 R4 V3 Answer: OV Using the above circuit, but consider the following component values: R1= 2 K12 R2=8 K2, R3=2.9 K2, R4=6 KI2, R5=10.8 K92, R6=15 KO, RL=10 K2, V1=1V, 12=0.5mA and V3=2V. What is the input impedance as seen by source V3?

Answer 1

I have solved the each part with proper circuit and calculations as shown below -

oufput voltage criculation in A 4.2 w Vo 14 V V T 8 m 1 1 Vol 10.3 a 0.5 6 501 T w 7 Ť 3.2v T ř + Vit 2.2 Sol ? solv,+ 6 Vp +1912 6x sol 11.1V =:-19.2 y=-1.72 v

taking Kel at Node A, V- Vo VI + you! 0.5 = 0 4.2 AS CH culoted abruy v=4.72 v putting in equation , after siorplifying 4V, -V.)+2017+8.4V, -8.4-8.4 16.8 =0 14.5V 4V- 16.8 14.5*(1.72) -16,8 = 480 VALI-4 Vo =-46.74 Vo =-10.43 volts

R = 2.942, R = bkn 2v OA I I have taken the required circuit mey. 6. kwa 2v + T Vt 2 + 2o9 6 6 V+12+zogv 8o9v=-2) XAT v= - 12 8.34v ㅍ -1.34 + 2 200227 mA gig ka Ri 13 2 8.81 kr I • 227 Ria 8.81 km