Question

X= 1, Y=1, Z= .01

Average value for the rate constant (Krate) based on the initial concentrations in Table 13.2 in your lab manual and the calculated values for x, y, and z that you determined earlier. Report your answer to 1 significant figure. -0.5 = krate (H2O2)" [1 -1 [H +)* total time Table 13.1. Preparation of Reaction Mixtures to be Studied Solution Water Buffer 0.3 M CH,COOH 0.05 MKI 1 5. Search 0.8 MH,O, 0.05 M NSO 0 ml 5 ml 5 ml 75 ml 0 ml 30 ml 30 ml 30 ml 5 ml 5 ml 10 ml 5 ml 10 ml 25 ml 25 ml 50 ml 25 ml Oml Oml 45 ml 50 ml 30 ml 5 ml 5 ml 5 ml 30 ml 10 ml 5 ml "Buffer is 0.05 Molar acetic acid + 0.05 Molar sodium acetate, A 3 % hydrogen peroxide solution sold in drugstores is about 0.8 Molar. 157 Table 13.2. Initial Molar Concentrations of Chemical Species in the Reaction Mixtures Solution TH,0:1 THI 0.00833 1 0.0533 0.0267 2 1.75 x 10 1.75 x 10 1.75 x 10 1.75 X 10 0.00833 0.0167 0.00833 0.0511 0.0533

S2O3^-2 =.002

Reaction Time: 436

Answer 1

Hi there,

You have provided all values to me and i am supposed to be calculate k_rate by substituting these input values into given formula

Please note that we have to select any 1 solution for consistency, i am gonna select solution-1

Further more i found moles S₂O₃^2- = 0.05 M x 5 mL x 10^-3 L = 0.00025 mol

total volume = 75 mL + 30 mL + 25 mL + 5 mL + 5 mL + 10 mL = 150 mL = 0.15 L

[S₂O₃^2-] = 0.00166666666 ~ 0.002 M

-0.5 x [[S₂O₃^2-] / total time] = k_rate x [H₂O₂]^x x [I^-]^y x [H⁺]^z

-0.5[0.002 / 436] = k_rate x [0.0533] x [0.00833][1.75 x 10^-5]^0.01

k_rate = [-0.5[0.002 / 436]] / [0.0533] x [0.00833][1.75 x 10^-5]^0.01

k_rate = -0.03064265171

k_rate = 0.03 ( 1 significant figure)

Hope this helped you!

Thank You So Much!

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