Question

Let's say you want to "float" a section of copper wire, which is 7.65 cm long and 2.34 mm in diameter within the magnetic field of Earth near the Earth's surface. Assume the magnetic field of Earth makes a 31° with respect to the horizontal and has a magnitude of 3.5.x 10-5 T. The current is flowing from west to east. See the diagram given below. 5.Draw a Free Body Diagram of the wire. 22 degrees 6. What is the value of current needed to suspend this section of copper wire? 7. What is the emf as a function of time produced in the wire due to its unbalanced force? How would this effect the current in the wire? Would its vertical position increase, decrease, or stay the same?

Please answer all the questions!!!

Answer 1

0 data from the given question Lenglt of the copper wire L = 7.65CM -2 = 7.65 X 10 m Diameter of the wire = 2.34 mm Radios 2.34 2 = 1017x10mm Angle made by the magnetic field with horizontal 0-310 magnetic field of earth - 35 Y 10T horizontal component of the magnetic Thus field, Br = B sino = 3.5X105X Sin31 =118710 1051.. the current The free body diagram of wire os shown below. carrying RH Q 10 o TO Suspend oo float a section of copper wise, the magnetic field due to the current carrying wire should be equal to the vertical component of the cortis magnetic field as shown above.

Moll2Y = 1-8 x 165 2 -7 where Mo = permeability of free space = HTXIENIA? using r= 1.177162 me corrent though the wire: 1-1.8 X 1538 3:34x6°/cunxio -0.008 A According to Faraday's law cmfc --dolde os magnetic flux--DA where For the wire dA = 200L Thus, e- -d dt at (Moule5X2002) (17 HO!!L) This will change the current on the loop, in which emf changes according to the tenz.dow on a direction opposite to the source producing it, this increasing of decreasing the current. The vertical position remains on unchanged thie magnetic independent of the vertical length L. since field and hence the current is: