Question

7. Find average kinetic energy of a molecule in a room at 25.0 degrees C? (assume air is an ideal gas)

Answer 1

Solution ) According to Kinetic Molecular Theory, the average kinetic energy of gas molecules is a function only of temperature.

The formula is

KE=3/2 kT

where T is the Kelvin temperature and k is Boltzmann's constant.

KE=3/2×1.381×10⁻²³J⋅K⁻¹×298.15K = 6.176 × 10⁻²¹ J

For a mole of molecules, the average kinetic energy is

((6.176×10⁻²¹J)/1molecule)×((6.022×10²³molecules)/1mol)

= 3.719 ×10³ J/mol = 3.719  kJ/mol

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