In fuel cell the reactio takes place as follows
anode reaction CH4 + H2O -------> CO2 + 8H+ + 8 e-
Cathode reaction 4O2 + 8H+ + 8 e- ---------> 4H2O
Overall reaction CH4 + 2O2 -----------> CO2 + 2H2O
So, from here it is clear that 1 mole of CH4 produces 8 moles of Hydrogen
So, molar mass of H = 1 g/ mol
no. of moles of H present = given mass/ molar mass = 4000 g/1 g = 4000 moles
So, no. of moles of CH4 present = 500 moles
molar mass of CH4 = 16 g/mol
So 500 moles = 500 moles * 16 g/moles = 8000 g = 8 kg
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26. Synthesis of Hydrogen (Step 2) When the CO produced in the steam-methane reforming reaction is reacted with more steam at 450 K, the water-gas shift reaction: CO(g) + H20(g) CO(g) + H2(g) produces more hydrogen. If the equilibrium partial pressures of the gases in the reactor are 0.35 atm H2O 0.24 atm CO, 4.47 atm H2, and 4.36 atm CO2, what is the value of K?
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