
Find the most general
antiderivative of
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-2.6+3 2 sec f(x) = () e 3.0
Compute f (x) for f(x)=tan(e-3x + sin 4x + 2) a. f(x)=(-3e-3x + 4cos 4x) sec?(e-3x + sin 4x+2) b. None of the other answers oc f'(x) = sec?(-e-3x + 4cos 4x) d. f'(x) =(e-3x + sin 4x) sec?(e-3x + sin 4x+1)
a) If f(0) = 5sec° 0 – sec°O + sec e Find: f'(0) b) If f(x)= xe * + In 8x3 +In( cos x) -2x e Find: f'O
Find f(x) if fx)= sec x-2e and f(0) 0 2
Find f(x) if fx)= sec x-2e and f(0) 0 2
Show that tan(x) – 1 2. Let y = sec(x) 1 + tan(x) y' sec(x) 3. Find all x-values where the graph of f(x) = x – 2 cos(x)has a horizontal tangent line.
Find the magnitude and directon of F +ū. 3.0 cm, 340 2.6 cm, 128° a. magnitude= 1.6 cm, ° - 40. c. magnitude=6.1 cm, - 42° d. magnitude = 5.6 cm, - -42° b. magnitude= 2.8 cm = 45°
31. [-/1 Points) DETAILS SCALCET8 3.3.027. If f(x) = 5 sec(x) - 3x, find f'(x). f'(x) = Need Help? Read It Watch It Talk to a Tutor 32. [-/2 points) DETAILS SCALCET8 3.3.028. If f(x) = 20% cos(x), find f '(x) and F"(x). F'(x) = F"(x) = Need Help? Read it Talk to a Tutor 33. [-/2 Points) DETAILS SCALCET8 3.3.029 If H() = sin(e), find Hle) and H) HO) = HD) -
7) f(x) = 3 sec(4x + 3 a. Amplitud: b. Periodo: c. Despl. Horizontal: d. Asintotas: e. Despl. Vertical: 8) f(x) =tan(4x - 3) a. Periodo: b. Despl. Horizontal: c. Asíntotas: d. Despl. Vertical: 9) f(x) = cot(4x - 5) a. Periodo: b. Despl. Horizontal: c. Asíntotas: d. Despl. Vertical:
A point charge with q1 = +2.6 C is located
at x = −3.0 m, y = 0, and a second point charge
with q2 = +6.7 C is at x = +1.0 m,
y = +2.0 m (see figure below).
y (u) 12 (a) What is the force exerted by q1 on q2? magnitude direction IN o counterclockwise from the +x-axis (b) What is the force exerted by q2 on q1? magnitude direction IN o counterclockwise from the +x-axis
4. (Sec. 5.2, 00) Let X and Y be continuous rvs with the joint f(x, y) = 2(x+y), for 0 <y <r <1 and 0 otherwise. (a) Find E(X+Y) and E[X - Y) (b) Find E[XY] (c) Find E[Y|X = x) and E[X Y = y). (d) Find Cov[X,Y]