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dynamics

Problem 4. Find the tension in each cord for the systems shown in Fig. (Neglect the mass of the cords.) (25 p) / / / / / 50°
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Answer #1

T​​​​​​1​​​ = 75.15 N. , T​​​​​​2​​​ = 63.05 N .

Initially, the free body diagram is drawn and the Tension in cable is shown with horizontal and vertical components .

The downloward force would be due to the mass 10 kg . And the downward force = mg = 10g .

Where, g is gravity.

I T₂ Sin (50 +40°) = lo los 50° 19.81) D Iza 1o Cos 500 (9-81) a Iz 6.427 19.81 Iz = 63.05 N Putting I in equation on T = (63

If any doubt kindly comment. Thank you.

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