Question

The weight distribution of parcels sent in a certain manner is normal with mean value 16 lb and standard deviation 3.6 lb. The parcel service wishes to establish a weight value c beyond which there will be a surcharge. in USE SALT What value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight? (Round your answer to four decimal places.) C = Ib You may need to use the appropriate table in the Appendix of Tables to answer this question.

Answer 1

Let X be a random variable denoting weight of parcel.

X~N(16,3.6^2)

So, 99% of parcels have weight less that

16+Z _{$\alpha$ =0.01}*3.6 =16+2.33*3.6= 24.388

So,the value of c is 24.388+1=25.388

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