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The weight distribution of parcels sent in a certain manner is normal with mean value 13...

The weight distribution of parcels sent in a certain manner is normal with mean value 13 lb and standard deviation 3.4 lb. The parcel service wishes to establish a weight value c beyond which there will be a surcharge. What value of c is such that 99% of all parcels are at least 1 lbunder the surcharge weight? (Round your answer to three decimal places.)

c =_____ lb

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Answer #1

Given that,

P(Z > -2.326) = 0.99

z = -2.326

Using z-score formula,

x = z * +

x = -2.326 * 3.4 + 13 = 5.092

c = 5.092 lb

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