Question

A cylindrical pressure vessel is constructed by welding steel plates together. The pressure vessel supports an internal pressure of 240 (psi). In addition the pressure vessel supports an axial load of 270000 (lbs.). The inner radius of the pressure vessel is 48 (inches) with a wall thickness of 0.3125 (inches). The plates are welded at 72 degrees from the horizontal. Determine:

a) the stresses perpendicular and parallel to the weld. Show the stresses on a properly oriented differential element.

The normal stress:

parallel to the weld is _____ (psi)

perpendicular to the weld is ______ (psi)

The shear stress:

parallel to the weld is _______(psi)

perpendicular to the weld is_______ (psi)

P Weld P Angle Weld

Answer 1

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P weld Р ☆ --X Longitudinal stress in a cylinder is given by Pr Tong = at Hoop stron in a cylinder is given by Pr , where, & inner radius of cylinder. t Thicknen of cylinder Giren, P=240 psi, t=0.3195 in pressure inside the cylinder. Thoop YE - o long- 240x640 - 9216 Psi 2x0.3125 240x483) = 18432 Psi 0.3125 o hoop 270000 Horizontal stress due to anial load (48+2x0.3125)?–4812] 4 = 5693 Psi op i. How zontal stress, la = 9216 +5693 = 14909 P.si perpendiculas stron ry = 18432 Ps; by Hele, (o= =-720) : Dos onton Premier le cas de o = on-ty sinao • Cast-144) yox TA = 18096 Psi + 14909 +18432 2 14909-18432 14909-18432 9 = 1036 Psi Sin E1440) Tos † 18432 2 18096 Psi Iweld .. Stress perpendiculas to weld = ro = 18096 PSi Strens parallel to weld = ?o= 1036P8 1026PS D 14909 psi 720