Suppose color blindness is a X linked trait in humans. It is also recessive. A phenotypically...
Suppose color blindness is a X linked trait in humans. It is also recessive. A phenotypically normal woman has a father with color blindness. This woman marries a man with normal vision. What is the chance of their children being color blind? What is the chance of their daughters being color blind?
Homework Answers
Ans: Woman genotype must be- X+Xc
Where X+ represents normal allele which she must have got from her mother.
and, Xc represents color blind allele which she must have got from her father.
If this woman marries a man with normal vision- X+Y
| X+ | Y | |
| X+ | X+X+ (Female-normal vision) | X+Y (Male-normal vision) |
| Xc | X+Xc (Female-normal vision) | XcY (Male-color blind vision) |
- Chance of their children being color blind- 1/4
- Chance of their daughter being color blind- Nil (As color blind gene is recessive).
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