Question

Just need parts e and f...

Electromotive force Name ED HW-19 X X X X x x X X 5. A wire loop with increasing counterclockwise current K(r) is moving with constant horizontal spoed v, into a region of uniform magnctic field Bn. At some instant in time, the electrons have a net velocity down and to the right, as shown below. a. In what dircction is the magnetic force on the negative clectron, given its ner velocity? h. If the clcctron is contined to move with the wire but has increasing current, in what direction should the clectron accelerate? Explain your reasoning, 27 c. What other force(s) act on the clectron? (Hint: You can treat this system mechanically by thinking of the sides of the wire as walls.) Explain. d. Draw a free-body diagram of the electron. c. A very short time later, the electron moves along the direction of its vclocity. Which force(s) do work on the electron? Explain. f. Show that the work done on the clectron simplifics to ev.B.dy, where dy is the length of a small step downward.

Answer 1

Ans f work done = force × displacement

W =force on electron × dy

Using right hand rule electron will move downward in wire due to magnetic force qV_oB_o

W= qV_oB_ody here q = e

So W= eV_oB_ody