Answer :- toks , new-mystery-closure , L, foo, x, z, curr, closure, y
Because this bindings are active in the closure returned by new-mystery-closure and all the other bindings are inactive in the closure returned by new-mystery-closure.
Question 10 (1 point) Consider the following Scheme code: Which bindings are active in the closure...
Explain the evaluation of the following Scheme code: (define x 10) (define y 11) (define proc2 (lambda () (cons x (cons y '())))) (define proc1 (lambda (x y) (proc2))) (define main (lambda () (cond ((zero? (read)) (proc1 5 20)) (else (proc2))))) (main)
Question 6 (1 point) Consider the following piece of code. What will the output be of this code? int foo() { int fun = 0; int bar (int fun) { fun = fun - 1; return fun 1; } return fun + bar (fun + 1); } print (foo ()); print (foo ()); -1 2 1 0
Consider the following in C
int main() { float x = 3.14, *p = &x; int r, a = 2, b[] = {5, 6, 7}; <more code here> r = Foo(x, p, &a, b) <more code here> } int Foo(float x,float y, int *z, int *w) { <Foo's code goes here> } statement in Foo result (assigned value) modify Foo's AF variables modify main's AF variables statement in Foo result (assigned value) modify Foo's AF variables modify main's AF variables...
Suppose you were debugging the push() function of your program. Which of the following variables would be accessible to the debugger before the function is called? static struct node *stack; static struct node *new_node() { int size = sizeof(struct node); return malloc(size); void push(void *value) { struct node *n = new_node(); n->value = value; n->next = stack; stack = n; return malloc(size); void push (void *value) { struct node *n = new_node(); n->value = value; n->next = stack; stack =...
Please answer both questions. Thanks
Question 24 (1 point) What value would be returned if the method mystery were called and passed the array values (1, 15, 37, 12) as its parameter? public static int mystery (int[] list) int x = 0; for (int i = 1; i < list.length; i++) { int y = list[i] - list [0]; if (y > x) x = Y } } return x; 29 35 1 36 Question 25 (1 point) What is...
List the five implementation models of parameter passing. Consider the following closure in JavaScript: 1- function makeAdder(x) { 2- return function(y) {return x + y;} 3- } . . . 4- var add1 = makeAdder(0); 5- var add2 = makeAdder(10); 6- document.write(add1(20)); 7- document.write(add2(20)); Questions: a) Show the output. b) What is the closure subprogram in this example? c) Explain how the variable x referenced at line 2 is bound.
Question 14 (1 point) Suppose the following function foo was called with a list of size 5. How many operations on the handler stack (push or pop) would result during the execution of the function? def foo (L) : r = 0 for x in L: try: # convert x to int = int (x]) r = r + S except ValueError: return 0 S return r 0 return r 0 2 5 O 12 10 6
Question 14 (1 point) Suppose the following function foo was called with a list of size 5. How many operations on the handler stack (push or pop) would result during the execution of the function? def foo (L): r = 0 for x in L: try: # convert x to int int (x]) r = r + S except ValueError: return 0 S return r 2 5 112 10 6
Question 9 (1 point) Given that the following code has executed, what is the value of mystery? If your answer is a string, surround it with single quotes. If it is a number, just write the number. If it is a Boolean, write either True or False with no quotes. If this code won't work (crashes or infinite loop), write error with no quotes. string1 = 'I heart mathematics.' mystery' i=0 while True: 130 mysterystringl [i] if ilen (stringl)1: break
The last 3 cases are tests .cpp files to test the code. The
language of this code must be C++ because that is the only I am
familiar with.
Soreland, a software company, is planning on releasing its first C++ compiler with the hopes of putting MiniSoft's Visual C++ out of business (that reminds me of another story). Consequently, Soreland has contracted with the Fruugle Corporation to design and build part of their compiler. Of course, since Fruugle gets all...