Question

O You receive a brochure from all the brochures that there is that you want to randomly select 18 ct by faculty and determine the class reach there shown in the No1.can you come awesome the pain may bed 34 30 28 27 35 38 24 33 27 31 28 29 ca Wite the aim mematically and entlyand 26 Which of the

Answer 1

The given data is 34, 30,27,35,30, 41,24,27, 32, 27, 38 33, 31, 28, 29, 28, 26 28 1 / Sample Size (n) 18 Samble mean (~) = Exi js (543) >> Samble mean () - 30.444 Sample 9.0 (5) {(x; ~ X² N-1 (84-30.444) 18-1 +(26-30.4443 328.444 Sample S.D (5) 4.395 cs Scanned with CamScanner

u = 32 Null hy bothesis (Ho) ; (claim) u <32 Alternative hypothesis (Ho): test left -tailed This corresponds for which t-test for one meam will beused a level is d=0.01 & Critical value. The given dif n-1 17 degrees of freedom is bor а left a taikd test is the Gritical Value to -2.567 Reject it HO it t < -2.567 Test statistic : The t-stest statistic is given to X-Mo son town ta n-l under Ho 30.444 32 E u .395 / Jis cs Scanned with CamScanner

the t-test statistic value 30.444 32 Ć 4.395/ITS -1.556 1.036 t -1.502 Decision about Hoi. Since it is observed that is then t=-1.502 > te -2.563 it that Alle fail to reject the the null Concluded hypothesis using P-value ! P-value P= P(ts-1.502) P=0.0757 is that Concluded it Here P: 0.0757 > 0.01 reject the null fail to hypothesis Ho Conclusion : fail to reject the null hypothesis. Therefore, there is not enough evidence to the claim at accept -0.01 level z cs Scanned with CamScanner