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26.6. Using the results from exercise 26.5 a, find the solution to y + 4y fo with y(0) = 0 and y(0) = 0 for each of the fol Please do b and d. The result for 26.5 a is below
26.5 a. C[SOL {[y + 4y]. [Y). + 4L[y]1, → = F(s) [s?Y(s) – s y(0) - y(o)] + 4Y(s) = F(s) 0 0 (52 + 4) Y() = f(s) Y(s) = F(
0 0
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Answer #1

d/ 26.5 a a, We t o 4 t get the solution, HH) = sin(2) Using y(t) = Ź S* sin(2x) sin (21+ --)) dx = ☆ 5* 2 sin(2x) sim (2+-2x

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