suppose the diameter of farmland is normally distributed with mean of 8.6 km and a standard...
suppose the diameter of farmland is normally distributed with mean of 8.6 km and a standard deviation of 2.7 km
i) what is the value of x such that the interval (8.6-x, 8.6+x) contains 94% of all diameter values?
ii) what is the probability that the diameter of a randomly selected farmland will be between 6.4 km and 12 km?
Homework Answers
![Solution XN Normal (el=8.6, 8=2.7) 94% 30/0 t 8.6 x 8.6 8.6 + 2 For 8.6 x Plz S2] = 0.03 From 2 table PLZ < -1.881] = 0.03 z](http://img.homeworklib.com/questions/031a5740-edfc-11ea-992f-0fcb3a80774e.png?x-oss-process=image/resize,w_560)
![p[-0.815 < Z < 1.259] = P[ za 1.259] P(Z < -0.8.15] 0.8 g 60 0.2075 0.6885 Answers x=5.0787 Pl between 6.4 and 12] = 0.6885](http://img.homeworklib.com/questions/04993180-edfc-11ea-9a28-e981027b79fc.png?x-oss-process=image/resize,w_560)
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suppose the diameter of farmland is normally distributed with
mean of 8.6 km and a standard...
suppose the diameter of farmland is normally distributed with mean of 8.6 km and a standard...
suppose the diameter of farmland is normally distributed with mean of 8.6 km and a standard deviation of 2.7 km what is the probability that the diameter of a randomly selected farmland will be between 6.4 km and 12 km?
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