Question

Step 11: Now since: 2T M= Put the value of constant M from Step 7 into the equation above and solve the equation for the gravity. Show all your work below. M Lexperiment) – 2.0027596 M=277 g

Answer 1

We have, $M = \frac{2 \pi}{\sqrt{g}}$

OR

27

Acceleration due to gravity, $g =\left [ \frac{2 \pi}{M} \right ]^2 = \frac{4 \pi^2}{M^2}$

Substituting :

$\Rightarrow g = \frac{4 \pi^2}{2.0027596^2} = 9.84 m/s^2 \rightarrow Answer$

which is accordance with the standard valuw of 9.81 m/s^2