Question

12100 x 104) zela x3 + 52.12 28. (5 points) [Objective 7.4] A spring with spring constant k=2100 N/m and a 10 ko block are located 3 m above ground level, labeled point A in the figure below. The spring is compressed by 40 cm and used to launch the block along the path shown. The slopes are frictionless, but on the 9 m long level portion of the track the coefficient of friction between the track and the block is 0.3. To what vertical height will the block rise? Use work-energy considerations to solve. 390 *A complete solution shows all steps! 3 m Show all work:

step by step and detail explanation please

Answer 1

At A Energy EA = 1 KAx² + nghi At B - E = mv By conservation of energy EA - EB 12 kan²+ nghi {mv = 2 kAx² + nghi vB = . ve - J I KAN? + maghi bm VB= 9.6125 m/s. Between B and c Initial Kinetic energy get dissipated in the form heat. due to friction and remaining is left as KE at c . so KEB= KE + H KE(= KEB-H ² mv² = {mve? - ung xL ve = Jul - unge & rc = 6.2833 m/s So, now, Ke at c gets converted to P. E to reach final height i mw? = mghf - 2.01 m 12 m 2 Final height = 2.01m.