Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride...

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Question

Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron.

3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s)

A mixture of 41.0 g of magnesium ( mm= 24.31 g/mol) and 175 g of iron(III) chloride ( mm= 162.2 g/mol) is allowed to react. MMof MgCl₂=105.216 g/mol.

1. What is the limiting reactant?

2. how many grams of excess reactants will remain?

3. How many grams of MgCl₂ will be formed?

4. If 142 g of MgCl₂ were formed, what is the percent yeild for the reaction? No decimals.

science chemistry

Answer 1

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