Question

Several published studies report that 77% of individuals who need a kidney transplant find a suitable donor when they register on lists of donors unrelated to their family. Consider a group of 10 people who need a kidney transplant and find the following probabilities. 1. The probability that the 10 patients will find a donor in the lists of unrelated donors is 2. The probability that at least 8 of the patients will find a donor in the lists of unrelated donors is 3. The probability that a at most 5 of the patients find a donor in the lists of unrelated donors is 4. The mean of the binomial distribution is 5. The standard deviation of the binomial distribution

Answer 1

n=10; 1. 10.0733 at leart & p=0.77 (Binomid distribution ) P(n) = MG ba (18h - 10/0.77 (0.23lo-n 10cm(0.77 (0.23]!º;n=0,1,2, -, 10. p/n = 10) = 10 .1% (0.77 (0.230 0.0732668 The probability is P ( 28) = P (n=8) +P 10=9) + PIN=10) = 106910-77% +0.33*+/6,161739 (0.23)'+000,00-73)%0.239 The procesinhh = 10.5863 (0.58628273) 3) plazi) = Plo) +81) +P12) +213 +P1M) + Pla=5) = 0.0000out 0.000014 +0.000284 +0.001865 +0.01092870-043903 Eno = 10X0.77-7.7 11.3308 Jloxo:77X0.23 3) The Standard deviation=50pll-b) = at most s -10.0570 0.056979 4) The mean