Homework Answers
We would be looking at the first question all parts here as:
a) Given that there is a 25% probability of contracting the disease, the probability that one of the 5 children has the disease is computed here as:
P(X = 1) = 5*0.25*(1 - 0.25)4 = 0.3955
Therefore 0.3955 is the required probability here.
b) Probability that no more than one of their children has the
disease is computed here as:
= P(X = 0) + P(X = 1)
= (1 - 0.25)5 + 0.3955
= 0.6328
Therefore 0.6328 is the required probability here.
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Use the following info to answer questions 12-13: Cystic Fibrosis is a disorder passed on genetically....
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For（d）
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3. Cystic fibrosis is a recessive genetic disorder that causes too much mucus to build up in the lungs. What rules of genetics do you need to use to solve this problem? a. b. Normal lung functioning (R) is dominant while having cystic fibrosis (r) is recessive. Jessica has cystic fibrosis while Jon is a carrier (a heterozygote). Use a Punnett square to predict the probability that one of their children will have cystic fibrosis. C. Genotypic ratio: Phenotypic Ratio:...
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