Question

2) An RLC series circuit with 150-ohm resistor, 25-mH inductor, and 2 microfarad-capacitor is powered by an AC voltage source with a peak voltage of 340V and a frequency of 660 Hz. (a) Find the peak current that flows in the circuit. (b) Determine the phase angle of the source voltage relative to the current. (c) Determine the peak voltage across the resistor and its phase angle relative to the voltage source. (d) Find the peak voltage across the inductor and its phase angle relative to the voltage source. (e) Find the peak voltage across the capacitor and its phase angle relative to the voltage source.

Answer 1

2 150 25 MH Doo auf th I t = 660HZ Upeak: 340 LU:211F = 27X660 w=4146.90 rad/see as for peak current have to find zo 7. R +joy - Xe) XL = Lola 4146.90 * 25-4103 = 103.67 12 4146.90x2x106 = 120.571 Za za 150 + j(103.67 – 120.57) 1116.90) 1502 + 116.9012 = 150.94 R Iso IZI - Lz I peak - V Peak 340 Z = 2.25 A a ) b) 150.94 © coso - R I56 z 950.94 6:39° 97 ou ū (Upeak) e peak&R 2.250x150 - 337.5 Loo

d ) Inductor vost peak Not [poak) = (frame) x 2-25% 103.67 290° = 233.25290° e) (Vreak) (I pean) Xc 2.250 120.57 2-900 o 271.282-90°