Question

of that step. The solution will . Subtract. Start every step of your solution by a receive no credits if includes irrelevant or no explanations. 3 2x + 8 x - 2 x² - 4 . Problem 2 Simplify using the properties of the exponents (exponent rules), write down the you use before each step. The solution will receive no credits if includes irrelevant or no rules. Final answer should be reported with positive exponents the final answer from rational exponent to radical notation. . (2x2y) 3 x20

Answer 1

(1) Now 22+ 8 3 n-2 n-4 3 n-2 2n+ 8 (x-2)(n+2) [:n-4 an-ph =(+2)(x-2)] 3(x+27 - (20+ 8) (22-2)(x+2) " [ L.C.M (x-2, (2-2) (112)) = (3-2)(x+2)] 3x+6-2n-g (292) (272) 11 (3x+6) - (2018) (26-2)(x+2) = (32 (32–2x) + (6-8) (2-2)(x+2) x + (-2) (n-2 (2+2) 27 2 - (8/2)(x+2) = x'ta Hence 3 2-2 2x+8 n-4 N+2

(2) 2 x2 ۱/3 zo ة ا = 2x7) C: ا == 2 لا 2 ) \ * لا - چه :: 7 =a وار - 2x3) - لا . (2 × 3 ) || (( [" ه ه - ر2 : 4b ( دلار در 2 2 1/3 او د لا x " ه : " رو ] (%) "* را 3" و = * !داد * 73 - 32 × 3/y