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Hrxn = + 97.7 kj/mol and Srxn = + 140.2 J/K mol Temperaute when spontaneus =
a reaction has a delta Hrxn= -133 Kj and delta Srxn= 317 J/K.
at what temperature is the change in entropy for the reaction equal
to the change in entropy for the surroundings?
Exercise 19.44 with feedback A reaction has AH 133 kJ and Asran 317 J/K. You may want to reference (D pages T80-793) section 19.5 while completing this problem Part A Al what temperature is the change in entropy for the reaction equal to the change in entropy...
A reaction has a AH of -122 kJ/mol and a AS of +231 J/mol K. When will this reaction proceed spontaneously? A. At all temperatures B. Not at any temperature C. At high temperatures only D. At low temperatures only
for the reaction abc + d <---> ab + cd, the change in Hrxn= -75 kj/mol, and Ea(fwd) is 235 kj/mol. assuming one step reaction, caluclate Ea(rev)
If ∆Hº = 220 kJ/mol and ∆Sº = –150 J/mol•K, calculate ∆Gº, in units of kJ/mol, at 25ºC
For a particular reaction at 205.1205.1 °C, ΔG=−45.90 kJ/molΔG=−45.90 kJ/mol, and ΔS=395.61 J/(mol⋅K)ΔS=395.61 J/(mol⋅K). Calculate ΔG for this reaction at −6.1−6.1 °C.
Consider a process at 286 K with ΔH = -72.5 kJ/mol and ΔS = -96.8 J/K mol Which of the following is true? ΔG = -19.1 kJ/mol and the process will not be spontaneous ΔG = -44.8 kJ/mol and the process will not be spontaneous ΔG = -44.8 kJ/mol and the process will be spontaneous ΔG = +39.4 kJ/mol and the process will not be spontaneous ΔG = +39.4 kJ/mol and the process will be spontaneous
Part AH X = 90 kJ , ASrxn = – 149 J/K , T = 293 K Express your answer using three significant figures. 10 AJO O O ? AG = Submit Request Answer Part D AHX = - 90 kJ, A Srxn = 149 J/K, T = 401 K Express your answer using three significant figures. IVO AQ R o o ?
If Assurr = -(5.71x10^2) J/mol K, what is the value of AHsys (in kJ/mol) at a constant temperature of (3.1900x10^2) K?
A reaction has and △H°298 = 106 kJ/mol and △S°298 = 326 J /mol K at 298 K. Calculate △G in kJ/mol.
Using the data: C2H4(g), = +51.9 kJ mol-1, S° = 219.8 J mol-1 K-1 CO2(g), = ‑394 kJ mol-1, S° = 213.6 J mol-1 K-1 H2O(l), = ‑286.0 kJ mol-1, S° = 69.96 J mol-1 K-1 O2(g), = 0.00 kJ mol-1, S° = 205 J mol-1 K-1 calculate the maximum amount of work that can be obtained, at 25.0 °C, from the process: C2H4(g) + 3 O2(g) → 2 CO2(g) + 2 H2O(l)