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P air=29.98 in Hg P H20= 23.060 torr T room= 22.7 C V gas=88.4 mL R=0.08206...

P air=29.98 in Hg

P H20= 23.060 torr

T room= 22.7 C

V gas=88.4 mL

R=0.08206 L atm/mol K

1. Using the balanced chemical equation write two conversion factors relating mol Mg to mol H2.

2. Covert Vgas, T room, P air, and P H2O into units consistent with the ideal gas law. (1 atm=29.92 in Hg and 1 atm = 760 torr)

3. Calculate the PH2 from the following: P air=P gas= PH2 + PH2O

4. Using these equivalencies write the values for the hydrogen collected: T room= T gas =TH2 and V gas =VH2

5.rearrange the ideal gas law to solve for the numbers of mole (nH2)

use the values for VH2, PH2, and TH2 to solve for nH2

6. Use the mole to mole conversion factor from #1 above to convert nH2 to nMg.

7. Calculate gram of Mg to mole Mg (nMG)

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