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Vectors A and B have scalar product -2.00 and their vector product has magnitude 6.00. Part A What is the angle between these
θtheta = ?

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scalare product is given by, À 8 = \A1 1B1Cose = -2 (gluen) cross product is given by Ax8 = 1911B1 sino = 6 (geren) - Now eq

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