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The value for the equilibrium constant for the following chemical reaction, the auto-ionization of water, is...

The value for the equilibrium constant for the following chemical reaction, the auto-ionization of water, is 1.0x10-14 at 298 K

2H2O(l) ßà OH-(aq) + H3O+(aq) K = 1.0x10-14

Using this information and your equilibrium identities, select the correct value for the equilibrium expression for the reaction shown below (at 298 K as well) :

OH-(aq) + H3O+(aq)  ßà 2H2O(l) K = ?

Question 4 options:

1x10-14

0.5x10-14

2x10-14

-1x10-14

1x1014

1x10-15
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