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A new fertilizer was applied to the soil of 81 bean plants. 52% showed increased growth....

A new fertilizer was applied to the soil of 81 bean plants. 52% showed increased growth. Find the margin of error and 95% confidence interval for this statistic. (Round all answers to 1 decimal place.) Margin of Error (as a percentage):_?_% Confidence Interval: _?_% to _?_%

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Answer #1

Answer:

Given,

p = 0.52

sample n = 81

Here at 95% CI, z value is 1.96

Margin of error = E = z*sqrt(pq/n)

substitute values

= 1.96*sqrt(0.52(1-0.52)/81)

= 0.1088

= 10.9%

95% CI = p +/- E

substitute values

= 0.85 +/- 0.1088

= (0.7412 , 0.9588)

= (74.1% , 95.9%)

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