Question

di 45-0.03 jt + 15: i = 6e-soot_3

Is it possible that answer for equation of 0.03t' + 15t = 45 is i = 6e^-500t - 3??? This answer from my lecturer.

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Answer #1

5oot_3, then it must 0.03 +151 = 46 Lets assume that is be satisfy the above differential equation, 0.03 od (be soot 3) + 15

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