Question

ere is only a single correct answer to all these questions. Question 1 Problem 1: Interpolation, least squares, and finite difference Consider the following data table: 0.2 0 2 2 2.018 2 f() = 3 0.4 2.104 0.6) L2.306) The linear Lagrange interpolator L1,1() used to linearly interpolate between data points x = 0.2 and x3 -0.4 is (Chop after 2 decimal places) 0 -5.00x+2.00 0 5.00x+2.00 None of the above. 0 2.50x+0.20 5.00x 1.00 Question 2 Problem 2: Interpolation, least squares, and finite difference Consider the following data table:

it is one question it just has many parts

Answer 1

( 1) X, 0.2 f) 2.018 az - 0.4 f(1) = 2.104 X-3 x- f(A) = (x) برا f(x) t -k. X-012 x 2.104 X-014 - X 21018 t 6.4-0.2 0.2 -0.4 + (X-012) X 2.104 (4-014 ) x 2.013 > 012 -012 ots [(-2.018 +2.104 ) x + 014x 2.018 – 012 0.2 x 2.104 4 ] oz [0.086 1 +603869] hyllyy 01434 + 11932 z 2.06 (2) 4,, (013) = 0.43x013 +11932 3) S₂ =012, Xz zo 14 2018 of 4) = 2 flah) = X, 50, f\})- 2.104) ) Asal d, zo, I = 0,2 x 10 = £ * = 233 f) = 2, FQ) = 1009 $09,) = 20 > 5 συ 125

사위 L(1) = 2 + (들x01x) 501 (톨97 에된 50m 이(이 ㅏ 263 125 (-) Soft) 유들아들 (\(-x) 10 1009 시가를 ( ) + + 2631%) S00 -2, 2 5 S 125 2 (+) 옳 1009 2름의 4 A + SCD 5 263 에 125 21 긁 20 251 1009 (시르름 바그쁨 시떻) - (2514-15143) + (Lear the 1 2 2 263 lo 263 50 17. 20 5 19 000842 N