Question

The figure below shows three charged particles arranged at the vertices of an isosceles triangle with base b = 2.60 m. What is the electric potential due to the particles at point P, which is at the midpoint of the base? (Consider the following values: GA - 2.90 pc, qe = 2.90 p. 4c = -2.90 C, 8 - 27.09) P Ano

Answer 1

V = 261 X10" [!5" 1.5151] 3 V 0.648 56 x 10 648-6 v

Solution qc C YA Р & B B a4 le & A=2.que, &B=2.9 me b=2.6m, qe = -2-quc = 27 'pi is given given by Now, Potential at point 'pi is v VA + VB + Vc - K&B < = t + KIA AP PB kle Pc here AP - BP 1.3m - с Pc PB tau o - 0 Pt 1.3m B pe= PB x tance PC = 1-3x tou(27) 0.66 m V = K 2.9x109 + 2.9x100 209 xlor 13 13 v = qx 109 x 29x109 "It has the motor