Question

QUESTION 16 A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (uk-0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? 1400 m 20 m 45° 20 m

Answer 1

halorem. A 90 kg skier at the top of a 400 m icy hill slides down, through a 20 m patch of snow (uk - 0.25) and hits a 20 m long jump ramp at a 45° incline. a) (10 points) How far from the edge of the ramp does the skier land (m)? 3 м To find our apply energy conservation Initial g.PE fristian work done by 1400 m 20 m mg14oo) HUN) (20) 45° =g.P.E at = mgcharz) top of ramp 20 m y graoo) - 10.250g (20) KE. + Inv? =gliore)+ v² |v=86.4 mis { N= mg z y From equation of motion Sy= Vost tl ay te ch: 86.4 Sin45° Z 9.82² ay * - 14:14= 61.1t - 4.92² => 4.94²-61-17 -14.14= 2 &t=12.7 sec .; R = (v cos 45º)t => R= 775.9m

For max.ht. Ny=o (vertical component of velocity at highest point] Vz-voy = 2 ay sy { Sy is from edge og ramp.] >Y 0 - (86.4 cos 45°)= 2(9.8)Sy = Sy=190.42 m. ;(1082 + 190.42 From ground Distance = 204.56 m