A skier slides down from the top of a frictionless 400 incline of height 205 m. If she starts from rest, calculate the speed of the skier at the bottom of the incline.
Solution:
Given:
Height of the incline (h) = 205 m
Since the inclined plane is friction-less.
According to conservation of energy: KEfinal = PEinitial
(1/2) mv2 = m g h
v2 = 2 g h
v2 = (2)(9.81 m/s2)(205 m) = 4022.1
v
= 63.42 m/s
Thus: the speed of the skier at the bottom of the incline is : v = 63.42 m/s
A skier slides down from the top of a frictionless 400 incline of height 205 m....
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points) How high will he get of the ground (max height (m)) ?
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