t = 1.77
n =23
df = 23- 1 = 22
(a) p value for Ho:
50
P value = TDIST (t statistics, df, tails) = TDIST (1.77, 22, 2) = 0.0906
(b)
p value for Ho:
> 50
P value = TDIST (t statistics, df, tails) = TDIST (1.77, 22, 1) = 0.0453 = 0.045
(c)
p value for Ho:
< 50
P value = TDIST (t statistics, df, tails) = TDIST (1.77, 22, 1) = 0.0453 = 0.045
A study has a random sample of 23 subjects. The test statistic for testing Ho: H=50...
A study has a random sample of 27 subjects. The test statistic for testing Upper H 0 : mu equals 150H0: μ=150 is tequals=2.53. Find the approximate P-value for the alternative a. Upper H Subscript a Baseline : muHa: μnot equals≠150, b. Upper H Subscript a Baseline : muHa: μgreater than>150, and c. Upper H Subscript a Baseline : muHa: μless than<150.
A study has a random sample of 29 test subjects. the test statistic for testing H0: u=100 is t= 1.81. find the approximate P- value for the alternative. A) Ha: u (does not equal) 100 p-value=?? B) Ha : u > 100 p-value=?? C) Ha: u < 100 p-value=??
A study uses a random sample of size 15. The test statistic for testing Upper H 0 : mu equals 12 versus Upper H Subscript a Baseline : mu not equals 12 is t equals negative 2.5 . Find the approximate P-value. Round your answer to two decimal places.
A study uses a random sample of size 15. The test statistic for testing Upper H 0 : mu equals 12 versus Upper H Subscript a Baseline : mu not equals 12 is t equals negative 2.5 . Find the approximate P-value. Round your answer to two decimal places. A. 0.013 B. 0.050 C. 0.990 D. 0.025 E. The P-value cannot be determined without the sample standard deviation. (please explain the steps using TI84 calculator and the keys to enter...
a through d please
To test Ho = 50 versus Hy < 50, a random sample of size n=23 is obtained from a population that is known to be normally distributed. Complete parts (a) through (d) below. Click here to view the t-Distribution Area in Right Tail (a) If x = 46 4 and s= 12.9, compute the test statistic. to-(Round to three decimal places as needed) (b) If the researcher decides to test this hypothesis at the a=0.05 level...
Question Help To test Ho: -50 versus H: <50, a random sample of size n=25 is obtained from a population that is known to be normally distributed. Complete parts (a) through (d) below. Click here to view the t-Distribution Area in Right Tai (a) If x= 46.6 and s-13.8, compute the test statistic. to=(Round to three decimal places as needed.) (b) If the researcher decides to test this hypothesis at the c 0.05 level of significance, determine the critical value(s)....
To test Ho: = 50 versus H=50, a simple random sample of size n = 40 is obtained. Complete parts (a) through below Click the icon to view the table of critical t-values (a) Does the population have to be normally distributed to test this hypothesis by using t-distribution methods? Why? O A. No-there are no constraints in order to perform a hypothesis test. O B. No-since the sample size is at least 30, the underlying population does not need...
The test statistic of z= 1.27 is obtained when testing the claim that p>0.7. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a = 0.05, should we reject H, or should we fail to reject H,? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. This is a right-tailed test. b....
help please !!
To test Ho: 0 = 2.3 versus H: > 2.3, a random sample of size n=20 is obtained from a population that is known to be normally distributed. (a) If the sample standard deviation is determined to be s 3.1. compute the test statistic (b) of the researcher decides to test this hypothesis at the a= 0.05 level of significance, use technology to determine the P-value. (c) Will the researcher reject the null hypothesis? (a) The test...
Consider a drug testing company that provides a test for marijuana usage. Among 250 tested subjects, results from 30 subjects were wrong (either a false positive or a false negative). Use a 0.05 significance level to test the claim that less than 10 percent of the test results are wrong. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A Ho: p=0.1 H, p<0.1 Ho: p=0.1 IPi1 Hp0.1 Ос. Ho: p<0.1 H, p=0.1 OD....